本帖最后由 Archimedes 于 2009-8-11 19:42 编辑
Dear Dr. Yue and other fellows,
quite funny... i think 2-d is enough to take the question into account since we need to find a local max or min value or if we can't find it out, a reasonable value under extreme circumstances should be find out at least.
labels are shown in to illustration. MD = R_m = 384400 km, SB = R_s = 1.496*10^8 km, and < MES = 57m21s are all known; SM can be worked out according to the sine formula; cos<BSM = (BS - MD)/SM, so <MSE can be worked out; hence we've <BSE = < BSM - < MSE.
MS = sqrt (SE^2 + ME^2 - 2*SE*ME*cos <MES) = 1.4922*10^8 km;
<BSM = 89deg44m0.99s; <MSE = 8.86s; => <SEP = <BSE = 89deg43m52.13s;
SE is parallel to ecliptic. (elongation 23deg27m) => central eclipse visible at two poles!? contradiction... awaiting good explanation...
Cheers, Man-To Hui
[values' errors corrected] |